Question:
The ratio of paint and oil in Tank A is 3: 4, whereas in Tank B, the respective ratio is 4: 5 . Then, 96 liters of a mixture consisting of paint and oil in the ratio of 5: 1 is added to Tank A, such that the respective ratio in Tank A becomes exactly the reverse of that in Tank B. Find the amount (in liters) of the mixture from Tank B that is poured into Tank A such that the amount of paint and water in Tank A become equal.
The ratio of paint and oil in Tank A is 3: 4, whereas in Tank B, the respective ratio is 4: 5 . Then, 96 liters of a mixture consisting of paint and oil in the ratio of 5: 1 is added to Tank A, such that the respective ratio in Tank A becomes exactly the reverse of that in Tank B. Find the amount (in liters) of the mixture from Tank B that is poured into Tank A such that the amount of paint and water in Tank A become equal.
Updated On: Aug 18, 2024
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The Correct Option is A
Solution and Explanation
Let the initial amount of mixture in Tank \(A\) be \(7x\).
The amount of paint and oil in \(96\) litres of mixture is \(80\) litres and \(16\) litres.
Thus given,
\(\frac{3x+80}{4x+16} =\frac{ 5}{4}\)
or, \(12x+320 = 20x+80\)
or, \(x = 30\)
Total mixture in Tank \(A\) = \(210+96 = 306\)
Thus, \(306\) litres from Tank \(B\) need to be poured into Tank \(A\).
Hence, option A is the correct answer.
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