Question:

The ratio of de Broglie wavelengths associated with thermal neutrons at temperatures 127°C and 352°C is

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Remember that temperature in de Broglie wavelength equations must be in Kelvin.
Updated On: Jun 6, 2025
  • 5 : 3
  • 3 : 2
  • 3 : 4
  • 3 : 5
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The Correct Option is A

Solution and Explanation

The de Broglie wavelength is given by: $$ \lambda = \frac{h}{\sqrt{2 m k T}} $$ where $h$ is Planck’s constant, $m$ is the mass of the particle, $k$ is Boltzmann’s constant, and $T$ is the temperature in Kelvin. The ratio of wavelengths depends on the square root of the inverse of the temperature ratio. Thus, the ratio of wavelengths at 127°C and 352°C is 5:3.
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