Question:

The ratio $C_p /C_v$ for a diatomic gas is more than that for a monotomic gas. The molecules of a monotomic gas have more degree of freedom than those of a diatomic gas.

Updated On: Jul 28, 2022
  • It both Assertion and Reason are true and the Reason is a correct explanation of the Assertion
  • If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion
  • If Assertion is true but the Reason is false
  • If both Assertion and Reason are false
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The Correct Option is D

Solution and Explanation

The ratio $\frac{C_{p}}{C_{V}}$ is given by, $\gamma=\frac{C_{p}}{C_{V}}=1+\frac{2}{n}$ where $n$ is the number of degrees of freedom. Since the number of degrees of freedom for monatomir. gas (3) is less than that of diatomic gas (5), $\gamma_{\text {monatomic }}>\gamma_{\text {dlatiomic }}$
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