Question:
The range of the function f(x) = 2sin(3x) +1 is equal to
The range of the function f(x) = 2sin(3x) +1 is equal to
Updated On: Aug 20, 2024
- [-1, 1]
- \([\frac{-1}{3},\frac{1}{3}]\)
- [-2, 1]
- [-1, 2]
- [-1, 3]
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The Correct Option is
Solution and Explanation
The correct option is (E) : [-1, 3]
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