$\frac{R}{4}$
Step 1: The moment of inertia of a solid cylinder about its central axis is: \[ I = \frac{1}{2} M R^2 \] Step 2: The radius of gyration $K$ is related to the moment of inertia by: \[ I = M K^2 \] Step 3: Equating both expressions: \[ M K^2 = \frac{1}{2} M R^2 \] \[ K^2 = \frac{R^2}{2} \] \[ K = \frac{R}{\sqrt{2}} \] Step 4: Therefore, the correct answer is (C).