The quadratic equation whose roots are sin218° and cos2 36° is
16x2 - 12x - 1 = 0
16x2 - 12x + 4 = 0
16x2 - 12x + 1 = 0
16x2 + 12x + 1 = 0
Step 1: Understanding the roots
The roots of the quadratic equation are \( \sin^2 18^\circ \) and \( \cos^2 36^\circ \). We need to form the quadratic equation with these as roots. The general form of the quadratic equation with roots \( r_1 \) and \( r_2 \) is given by:
\( (x - r_1)(x - r_2) = 0 \), where \( r_1 = \sin^2 18^\circ \) and \( r_2 = \cos^2 36^\circ \).
Step 2: Using the identity for a quadratic equation
The sum of the roots of the quadratic equation is given by \( r_1 + r_2 = \sin^2 18^\circ + \cos^2 36^\circ \), and the product of the roots is \( r_1 \times r_2 = \sin^2 18^\circ \times \cos^2 36^\circ \).
Step 3: Calculate sum and product of the roots
First, we need the values of \( \sin 18^\circ \) and \( \cos 36^\circ \). Using a calculator or trigonometric tables, we find:
\( \sin 18^\circ \approx 0.3090 \) and \( \cos 36^\circ \approx 0.8090 \).
Now, calculate their squares:
\( \sin^2 18^\circ \approx (0.3090)^2 = 0.0955 \) and \( \cos^2 36^\circ \approx (0.8090)^2 = 0.6545 \).
Thus, the sum of the roots is:
\( r_1 + r_2 = 0.0955 + 0.6545 = 0.75 \).
The product of the roots is:
\( r_1 \times r_2 = 0.0955 \times 0.6545 = 0.0625 \).
Step 4: Form the quadratic equation
The quadratic equation with roots \( r_1 \) and \( r_2 \) is:
\( x^2 - (r_1 + r_2)x + r_1 \times r_2 = 0 \). Substituting the values we found:
\( x^2 - 0.75x + 0.0625 = 0 \).
Step 5: Compare with the options
We now compare the derived equation \( x^2 - 0.75x + 0.0625 = 0 \) with the given options. The equation closest to this form is:
\( 16x^2 - 12x + 1 = 0 \).
Final Answer:
The quadratic equation whose roots are \( \sin^2 18^\circ \) and \( \cos^2 36^\circ \) is:
\( 16x^2 - 12x + 1 = 0 \).
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to:
A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers.
Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.
The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)
Read More: Nature of Roots of Quadratic Equation