Question

The products formed in the following reaction, A and B, are: \begin{center} \includegraphics[width=8cm]{77.png} \end{center}

• A. \includegraphics[width=5cm]{77a.png}
• B. \includegraphics[width=5cm]{77b.png}
• C. \includegraphics[width=5cm]{77c.png}
• D. \includegraphics[width=5cm]{77d.png}

Hint:

Tollens' reagent oxidizes aldehydes to carboxylic acids, while sodium borohydride reduces ketones and aldehydes to alcohols.

Answer 1

The Correct Option is C

The reaction proceeds in two stages: Step 1: Oxidation with Tollens' Reagent - Tollens' reagent \([Ag(NH_3)_2]^+ \, \text{and} \, OH^-\) selectively oxidizes aldehydes to carboxylic acids. - In this case, the aldehyde group (\(-CHO\)) of the compound undergoes oxidation to form a carboxylic acid group (\(-COOH\)). - The resulting product \( A \) after oxidation is: \[ \text{A} = \text{Compound with the aldehyde oxidized to a carboxylic acid: } \text{HCOOH}. \] Step 2: Reduction with Sodium Borohydride - Sodium borohydride (\( NaBH_4 \)) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols. - In the given compound, the ketone group (\(-C=O\)) is reduced to a secondary alcohol (\(-CH(OH)-\)). - The product \( B \) after reduction is: \[ \text{B} = \text{Compound with the ketone reduced to an alcohol: } \text{HCOOH}. \] Final Answer: The products \( A \) and \( B \) correspond to: \[ \boxed{\text{Option C}} \]