Question

The products formed in the following reaction, A and B, are: 

• A.

  

• B.

  

• C.

  

• D.

  

Hint:

Tollens' reagent oxidizes aldehydes to carboxylic acids, while sodium borohydride reduces ketones and aldehydes to alcohols.

Answer 1

The Correct Option is C

The reaction proceeds in two stages:

Step 1: Oxidation with Tollens' Reagent

• Tollens' reagent \([Ag(NH_3)_2]^+ \, \text{and} \, OH^-\) selectively oxidizes aldehydes to carboxylic acids.
• In this case, the aldehyde group (\(-CHO\)) of the compound undergoes oxidation to form a carboxylic acid group (\(-COOH\)).
• The resulting product \( A \) after oxidation is: \[ \text{A} = \text{Compound with the aldehyde oxidized to a carboxylic acid: } \text{HCOOH}. \]

Step 2: Reduction with Sodium Borohydride

• Sodium borohydride (\( NaBH_4 \)) is a selective reducing agent that reduces aldehydes and ketones to their corresponding alcohols.
• In the given compound, the ketone group (\(-C=O\)) is reduced to a secondary alcohol (\(-CH(OH)-\)).
• The product \( B \) after reduction is: \[ \text{B} = \text{Compound with the ketone reduced to an alcohol: } \text{HCOOH}. \]

Final Answer: The products \( A \) and \( B \) correspond to:

\[ \boxed{\text{Option C}} \]