Question

The product ‘P’ is

• A.
• B.
• C.
• D.

Answer 1

The Correct Option is D

This reaction is a type of Aldol condensation reaction. The reaction involves the condensation of benzaldehyde (\(\text{C}_6\text{H}_5\text{CHO}\)) and acetaldehyde (\(\text{CH}_3\text{CHO}\)) in the presence of dilute NaOH. The condensation leads to the formation of an enolate ion, which then reacts with another molecule of aldehyde.

The reaction produces a product in which the aldehyde group from one molecule reacts with the carbon-carbon bond from another molecule to form a conjugated product. The product of this reaction is cinnamaldehyde (\(\text{C}_6\text{H}_5\text{CH} = \text{CHCHO}\)), which has both an aldehyde group and a double bond.

Thus, the product 'P' is cinnamaldehyde.

The correct option is : (D)

Answer 2

This is a case of the aldol condensation reaction. In the presence of dilute NaOH, benzaldehyde (C\(_6\)H\(_5\)CHO) and acetaldehyde (CH\(_3\)CHO) undergo an aldol reaction, where the alpha hydrogen of acetaldehyde is deprotonated by the base (NaOH) to form an enolate ion. This enolate ion then attacks the carbonyl carbon of benzaldehyde.

The intermediate aldol product formed initially is a β-hydroxy aldehyde. Upon heating (Δ), this undergoes dehydration (removal of a water molecule), forming a conjugated enone product, which is an α,β-unsaturated aldehyde.

Thus, the product formed is C\(_6\)H\(_5\)CH=CHCHO (a styrene derivative with an aldehyde group), which corresponds to option (D).