To solve the problem, we need to compute the expected value \( E(X) \) of the given discrete probability distribution.
1. Use the Formula for Expected Value:
The expected value \( E(X) \) is given by:
\( E(X) = \sum [x_i \cdot P(x_i)] \)
2. Substitute the Given Values:
\[
E(X) = (-4)(0.1) + (-3)(0.2) + (-2)(0.3) + (-1)(0.2) + (0)(0.2)
\]
\[
= -0.4 + (-0.6) + (-0.6) + (-0.2) + 0
\]
\[
= -0.4 - 0.6 - 0.6 - 0.2 = -1.8
\]
3. Conclusion:
The expected value of the distribution is \( -1.8 \)
Final Answer:
The correct option is (A) -1.8.
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]