Question:

The power of a thin convex lens placed in air is \( +4D \). The refractive index of the material of the convex lens is \( \frac{3}{2} \). If this convex lens is immersed in a liquid of refractive index \( \frac{5}{3} \), then: 

Show Hint

When a lens is placed in a medium of refractive index higher than its own, it behaves oppositely (i.e., a convex lens acts as a concave lens and vice versa). The power can be determined using the modified lens maker's formula.
Updated On: Mar 13, 2025
  • It behaves like a convex lens of focal length 75 cm
     

  • It behaves like a convex lens of focal length 125 cm
     

  • It behaves like a concave lens of focal length 125 cm
     

  • It behaves like a concave lens of focal length 75 cm

Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation


Step 1: Using Lens Maker's Formula 
The power of a lens in air is given by the lens maker's formula: \[ P_{\text{air}} = \left( \frac{n_L}{n_A} - 1 \right) \frac{100}{f} \] where \( P_{\text{air}} = +4D \), \( n_L = \frac{3}{2} \) (refractive index of lens), and \( n_A = 1 \) (refractive index of air). The focal length in air is: \[ f_{\text{air}} = \frac{100}{P_{\text{air}}} = \frac{100}{4} = 25 \text{ cm}. \] 

Step 2: Finding Power in the Liquid Medium 
When the lens is placed in a medium of refractive index \( n_M = \frac{5}{3} \), the power is given by: \[ P_{\text{liquid}} = \left( \frac{n_L}{n_M} - 1 \right) \frac{100}{f_{\text{air}}}. \] Substituting the values: \[ P_{\text{liquid}} = \left( \frac{\frac{3}{2}}{\frac{5}{3}} - 1 \right) \frac{100}{25}. \] Simplifying: \[ P_{\text{liquid}} = \left( \frac{3}{2} \times \frac{3}{5} - 1 \right) \times 4. \] \[ P_{\text{liquid}} = \left( \frac{9}{10} - 1 \right) \times 4. \] \[ P_{\text{liquid}} = \left( -\frac{1}{10} \right) \times 4. \] \[ P_{\text{liquid}} = -0.4D. \] Since the power is negative, the lens behaves as a concave lens. The focal length is: \[ f_{\text{liquid}} = \frac{100}{|P_{\text{liquid}}|} = \frac{100}{0.8} = 125 \text{ cm}. \] 

Step 3: Conclusion 
Thus, the lens behaves like a concave lens with a focal length of 125 cm: \[ \boxed{\text{it behaves like a concave lens of focal length 125 cm}}. \] 

Was this answer helpful?
0
0

Top Questions on Ray optics and optical instruments

View More Questions