
In position-time graphs, the slope represents speed, and the y-intercept at a given time represents distance.
(A), (C) and (E) only
(A) and (E) only
(B) and (E) only
(A), (C) and (D) only
The slope of A is given as:
\( \text{slope}_A = V_A \)
The slope of B is given as:
\( \text{slope}_B = V_B \)
Since:
\( \text{slope}_B > \text{slope}_A \)
It follows that:
\( V_B > V_A \)
As velocity (\( V \)) is inversely related to time (\( t \)) for a given distance:
\( t_B < t_A \)
The final answer is: (A) and (E) only.
A person moved from A to B on a circular path as shown in figure If the distance travelled by him is 60 m, then the magnitude of displacement would be Given ( Cos 135° = -0.7)

An object is projected with kinetic energy K from point A at an angle 60° with the horizontal. The ratio of the difference in kinetic energies at points B and C to that at point A (see figure), in the absence of air friction is : 
Two point charges 2q and q are placed at vertex A and centre of face CDEF of the cube as shown in figure. The electric flux passing through the cube is : 