Question

100 Vernier scale divisions match with 99 main scale divisions of a slide caliper. If the value of each main scale division is 1 mm, then the Vernier constant is:

• A. 1 mm
• B. 100 µm
• C. 10 µm
• D. 1 µm

Hint:

The Vernier constant is calculated by dividing the length of one main scale division by the number of Vernier scale divisions.

Answer 1

The Correct Option is C

To determine the Vernier constant, we need to find the difference between one main scale division and one Vernier scale division.

Given:

• 1 main scale division (MSD) = 1 mm
• 100 Vernier scale divisions (VSD) = 99 main scale divisions

We need to find the length of 1 Vernier scale division (1 VSD):

\(1 \text{ VSD} = \frac{\text{value of 99 MSDs}}{100} = \frac{99 \text{ mm}}{100} = 0.99 \text{ mm}\)

Therefore, the difference between one main scale division and one Vernier scale division (the Vernier constant) is:

\[ \text{Vernier Constant} = 1 \text{ MSD} - 1 \text{ VSD} \]

\[ = 1 \text{ mm} - 0.99 \text{ mm} = 0.01 \text{ mm} \]

Since 0.01 mm is equivalent to 10 micrometers (µm), the Vernier constant is:

10 µm

Answer 2

The Vernier constant is the difference between one main scale division and one Vernier scale division: \[ \text{Vernier constant} = \frac{\text{Length of 1 main scale division}}{\text{Number of divisions on Vernier scale}} = \frac{1 \, \text{mm}}{100} = 0.01 \, \text{mm} = 10 \, \mu\text{m} \] Thus, the Vernier constant is 10 µm.