Step 1: The position of the centre of mass of a uniform plate can be calculated by using the formula for the centre of mass of a rectangular body. For a uniform rectangular plate of dimensions \( a \times b \), the centre of mass lies at the intersection of the diagonals.
Step 2: For a uniform plate, the coordinates of the centre of mass are given by:
\[ \left( \frac{a}{2}, \frac{b}{2} \right) \]
where \( a \) and \( b \) are the length and width of the plate, respectively, and the origin is taken at one corner of the plate.
Step 3: If the plate is located such that the origin is at a point shifted from the center of the plate, the position of the centre of mass will be shifted accordingly.
Step 4: The position of the centre of mass relative to the given origin in the figure (assuming a symmetric uniform plate) will be:
\[ \left( -\frac{a}{6}, -\frac{b}{6} \right) \]
This represents the correct coordinates for the centre of mass based on the dimensions and position of the plate in the figure.
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of: