Question:
The point (2,-3) divides the line segment joining the points (-1,3), (4, -7) in the ratio ______ .
The point (2,-3) divides the line segment joining the points (-1,3), (4, -7) in the ratio ______ .
Updated On: Apr 29, 2024
- 3:2
- 2:3
- 8:1
- 1:4
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The correct option is (A): 3:2.
Was this answer helpful?
0
0
Top Questions on Section Formula
- Find the co-ordinates of the point which divides the line segment joining the points $A(3,4)$ and $B(-2,-1)$ in the ratio $3:2$.
- UP Board X - 2025
- Mathematics
- Section Formula
- Find the ratio in which Y-axis divides the line segment joining the points $(5,-6)$ and $(-1,-4)$.
- UP Board X - 2025
- Mathematics
- Section Formula
- If the plane \[ x - y + z + 4 = 0 \] divides the line joining the points \[ P(2,3,-1) \quad \text{and} \quad Q(1,4,-2) \] in the ratio \( l:m \), then \( l + m \) is:
- AP EAPCET - 2024
- Mathematics
- Section Formula
- The coordinates of the point which divides the line segment joining the points \((4, -3)\) and \((8, 5)\) in the ratio 3:1 internally is:
- TS POLYCET - 2024
- Mathematics
- Section Formula
- In what ratio the line segment joining the points (-2, 3) and (3, -7) is divided by x-axis ?
- CUET (UG) - 2023
- Mathematics
- Section Formula
View More Questions
Questions Asked in TS POLYCET exam
- If the pair of equations \( 3x + 4y = k \) and \( 9x + 12y = 6 \) has infinite number of solutions, then the value of k is:
- TS POLYCET - 2025
- Lines and Angles
- What is the nature of a solution whose pH value is 'zero'?
- TS POLYCET - 2025
- pH value
- Tesla is the SI unit of:
- TS POLYCET - 2025
- Kirchhoff's Laws
- The volume of CO\(_2\) liberated in litres at STP when 25 g of CaCO\(_3\) is treated with dilute HCl containing 14.6 g of HCl is:
- TS POLYCET - 2025
- Chemical Reactions
- Median of \( x, 20x, \frac{x}{20}, 200x, \frac{x}{200} \) (where \( x>0 \)) is 20, then the value of \( x \) is:
- TS POLYCET - 2025
- Solution of a Linear Equation
View More Questions