The buffer system consists of acetic acid (weak acid) and sodium acetate (its conjugate base). The pH of the buffer solution and the concentrations of the acid and its conjugate base are given.
Step 2: Using the Henderson-Hasselbalch EquationThe Henderson-Hasselbalch equation is used to calculate the \( \text{p}K_a \) of a buffer solution:
\[ \text{pH} = \text{p}K_a + \log\left(\frac{[\text{Conjugate Base}]}{[\text{Acid}]}\right) \] Step 3: Inserting the Given ValuesGiven that the pH is **5**, the concentration of the conjugate base (sodium acetate) is **0.4 M**, and the concentration of the acid (acetic acid) is **0.04 M**, we substitute these values into the equation:
\[ 5 = \text{p}K_a + \log\left(\frac{0.4}{0.04}\right) \] \[ 5 = \text{p}K_a + \log(10) \] \[ 5 = \text{p}K_a + 1 \] Step 4: Solving for \( \text{p}K_a \) \[ \text{p}K_a = 5 - 1 \] \[ \text{p}K_a = 4 \] Conclusion:Explanation: The calculated \( \text{p}K_a \) value is **4**, indicating the acid dissociation constant of acetic acid under the conditions of the buffer system provided.
The \( F_{121} \) value of a known microorganism with \( Z \) value of \( 11^\circ C \) is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at \( 143^\circ C \), the \( F \) value (in min) is .......... (rounded off to 3 decimal places)
Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?
Note: The figure shown is representative.
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?