Question:

Find the pH of the solution if \( [\text{H}^+] = 2 \times 10^{-4} \, \text{mol/L} \).

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To calculate the pH, use the formula \( \text{pH} = -\log[\text{H}^+] \). Remember that the concentration of hydrogen ions determines the acidity of the solution.
Updated On: Apr 24, 2025
  • 3.0
  • 3.7
  • 4.5
  • 5.0
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The Correct Option is B

Solution and Explanation

The pH of a solution is calculated using the formula: \[ \text{pH} = -\log[\text{H}^+] \] Where \( [\text{H}^+] \) is the concentration of hydrogen ions in the solution.

1. Step 1: Substitute the given value of \( [\text{H}^+] \). We are given \( [\text{H}^+] = 2 \times 10^{-4} \, \text{mol/L} \). Substituting this value into the pH formula: \[ \text{pH} = -\log(2 \times 10^{-4}) \]

2. Step 2: Simplify the expression. Using logarithmic properties: \[ \text{pH} = -\log(2) - \log(10^{-4}) = -\log(2) + 4 \] Since \( \log(2) \approx 0.3010 \), we have: \[ \text{pH} = -0.3010 + 4 =
3.7 \] Thus, the pH of the solution is \(
3.7 \).
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