Question:
The particle \( x \) in the following nuclear reaction is:
\[
^9_4Be + ^4_2He \rightarrow ^{12}_6C + x
\]
The particle \( x \) in the following nuclear reaction is:
\[ ^9_4Be + ^4_2He \rightarrow ^{12}_6C + x \]
\[ ^9_4Be + ^4_2He \rightarrow ^{12}_6C + x \]
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Nuclear reactions must conserve both mass and charge.
Updated On: Mar 26, 2025
- electron
- proton
- neutron
- photon
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The Correct Option is C
Solution and Explanation
Balancing the mass number and atomic number,
\[ 9 + 4 = 12 + A_x \quad \text{and} \quad 4 + 2 = 6 + Z_x \] Solving,
\[ A_x = 1, \quad Z_x = 0 \] which corresponds to a neutron.
\[ 9 + 4 = 12 + A_x \quad \text{and} \quad 4 + 2 = 6 + Z_x \] Solving,
\[ A_x = 1, \quad Z_x = 0 \] which corresponds to a neutron.
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