Question

The P-V diagram of a diatomic ideal gas system undergoing a cyclic process is shown in the figure. The work done during the adiabatic process \( CD \) is (Use \( \gamma = 1.4 \)): 
 

• A. \( -500J \)
• B. \( 200J \)
• C. \( -400J \)
• D. \( 400J \)

Hint:

For adiabatic processes:
- Work done is given by \( W = \frac{P_1 V_1 - P_2 V_2}{\gamma - 1} \).
- No heat exchange occurs, so \( Q = 0 \).
- The internal energy change is \( \Delta U = W \).

Answer 1

The Correct Option is A

Step 1: The work done in an adiabatic process is given by:
\[ W = \frac{P_1 V_1 - P_2 V_2}{\gamma - 1} \] Step 2: Substituting the given values, we solve for \( W \) and obtain:
\[ W = -500J \]