Question:
The oxidation state of the most electronegative element in the products of the reaction. $ BaO_2 $ with dil, $ H_2SO_4 $ are
The oxidation state of the most electronegative element in the products of the reaction. $ BaO_2 $ with dil, $ H_2SO_4 $ are
Updated On: June 02, 2025
- 0 and - 1
- - 1 and - 2
- - 2 and 0
- - 2 and - 1
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The Correct Option is D
Solution and Explanation
The correct option is(D): - 2 and - 1.
The reaction involved is \(BaO_2 + H_2SO_4 \rightarrow BaSO_4 + H_2O_2\) The most electronegative atom, oxygen, in \(BaSO_4\) and
\(H_2O_2\) has - 2 and - 1 oxidation state respectively.
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