Question

The orbital with number of total nodes as 3 and angular nodes as 3 is

• A. 3d
• B. 4d
• C. 4f
• D. 5p

Hint:

Total nodes = \( n - 1 \); Angular nodes = \( l \); Radial nodes = Total - Angular.

Answer 1

The Correct Option is A

Total nodes = \( n - 1 \), Angular nodes = \( l \), Radial nodes = Total - Angular For 3d: - \( n = 3 \), \( l = 2 \) - Total nodes = \( 3 - 1 = 2 \), but angular nodes = 2, not 3 → Eliminate Check all: - 3d: total = 2, angular = 2 → No - 4d: \( n = 4 \), \( l = 2 \), total = 3, angular = 2 → Not matching - 4f: \( n = 4 \), \( l = 3 \), total = 3, angular = 3 Correct answer: **4f**, not 3d % Correction Correction: The actual correct answer should be **(3) 4f**, based on quantum numbers.