Question:
The orbital with number of total nodes as 3 and angular nodes as 3 is
The orbital with number of total nodes as 3 and angular nodes as 3 is
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Total nodes = \( n - 1 \); Angular nodes = \( l \); Radial nodes = Total - Angular.
Updated On: Jun 3, 2025
- 3d
- 4d
- 4f
- 5p
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The Correct Option is A
Solution and Explanation
Total nodes = \( n - 1 \), Angular nodes = \( l \), Radial nodes = Total - Angular
For 3d:
- \( n = 3 \), \( l = 2 \)
- Total nodes = \( 3 - 1 = 2 \), but angular nodes = 2, not 3 → Eliminate
Check all:
- 3d: total = 2, angular = 2 → No
- 4d: \( n = 4 \), \( l = 2 \), total = 3, angular = 2 → Not matching
- 4f: \( n = 4 \), \( l = 3 \), total = 3, angular = 3
Correct answer: **4f**, not 3d
% Correction
Correction: The actual correct answer should be **(3) 4f**, based on quantum numbers.
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