Question

Among the following, the CORRECT combinations are
A. \( \mathrm{IF_3} \rightarrow \) T-shaped (\( sp^3d \))
B. \( \mathrm{IF_5} \rightarrow \) Square pyramidal (\( sp^3d^2 \))
C. \( \mathrm{IF_7} \rightarrow \) Pentagonal bipyramidal (\( sp^3d^3 \))
D. \( \mathrm{ClO_4^-} \rightarrow \) Square planar (\( sp^2d \))
Choose the correct answer from the options given below:

• A. A, B, C and D
• B. B, C and D only
• C. A and B only
• D. A, B and C only
  \bigskip

Hint:

Hybridization is determined by the total number of sigma bonds and lone pairs around the central atom.

Answer 1

The Correct Option is A

Step 1: Geometry of IF$_3$.
IF$_3$ has two lone pairs and three bond pairs with $sp^3d$ hybridization, giving a T-shaped geometry.
Step 2: Geometry of IF$_5$.
IF$_5$ has one lone pair and five bond pairs with $sp^3d^2$ hybridization, giving square pyramidal geometry.
Step 3: Geometry of IF$_7$.
IF$_7$ has seven bond pairs and no lone pair with $sp^3d^3$ hybridization, giving pentagonal bipyramidal geometry.
Step 4: Geometry of ClO$_4^-$.
ClO$_4^-$ has $sp^2d$ hybridization and square planar electron geometry.
Step 5: Conclusion.
All given combinations are correct.