The octahedral diamagnetic low spin complex among the following is
Show Hint
In octahedral complexes, the ligand field strength determines whether the com plex will be high spin or low spin.
- [CO(NH3)6]3+
- [COF6]3-
- [COCl6]3-
- [Fe(H2O)6]3+
The Correct Option is A
Solution and Explanation
Step 1: Understanding Coordination Complexes
The coordination number (CN) for [Co(NH3)6]3+ is 6, indicating an octahedral geometry. Ammonia (NH3) is a strong field ligand (SFL) as per the spectrochemical series.
Step 2: Electron Configuration of Co3+
- Atomic configuration of Co: \([Ar] 3d^7 4s^2\)
- Configuration of Co3+ (after losing 3 electrons): \([Ar] 3d^6\)
Step 3: Effect of Strong Field Ligand
Due to the strong field nature of NH3, it causes pairing of electrons in the 3d orbitals. The electronic configuration of Co3+ in the presence of NH3 becomes:
\[ t_{2g}^6 \, e_g^0 \]
This configuration indicates:
- All electrons are paired, making the complex diamagnetic.
- It is a low-spin octahedral complex.
Conclusion:
[Co(NH3)6]3+ is a diamagnetic, low-spin octahedral complex.
Final Answer: [Co(NH3)6]3+ is the correct option.
Top Questions on coordination compounds
- The metal ion whose electronic configuration is not affected by the nature of the ligand and which gives a violet color in non-luminous flame under hot condition in borax bead test is:
- JEE Main - 2025
- Chemistry
- coordination compounds
The structure of the major product formed in the following reaction is:
- JEE Main - 2025
- Chemistry
- coordination compounds
The steam volatile compounds among the following are:
- JEE Main - 2025
- Chemistry
- coordination compounds
The structure of the major product formed in the following reaction is:
- JEE Main - 2025
- Chemistry
- coordination compounds
- (b) Write two consequences of lanthanide contraction.
- CBSE CLASS XII - 2025
- Chemistry
- coordination compounds
Questions Asked in JEE Main exam
- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
- JEE Main - 2025
- Matrices and Determinants
- The product B formed in the following reaction sequence is: \[ {C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B) \]
- JEE Main - 2025
- Organic Chemistry
- What are the units of viscosity, intensity of wave, and pressure gradient?
- JEE Main - 2025
- Units and measurement
- If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
- JEE Main - 2025
- Matrices and Determinants
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.