Question:

The number of ways in which the letter of the word 'VERTICAL' can be arranged without changing the order of the vowels is 

Updated On: Apr 11, 2025
  • 6!×3!

  • \(\frac{8!}{3}\)
  • 6!×3

  • \(\frac{8!}{3!}\)
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The Correct Option is D

Approach Solution - 1

  1. The word VERTICAL has 8 letters
  2. It contains 3 vowels: E, I, and A.
  3. We want to arrange the letters without changing the order of the vowels, so we focus on placing the consonants: V, R, T, C, and L.

We must choose 3 positions out of 8 to place the vowels (in fixed order), and fill the rest with the 5 consonants.

Number of ways to choose 3 vowel positions from 8: $^8C_3$

Number of ways to arrange the remaining 5 consonants: $5!$

Total number of valid arrangements: $^8C_3 \times 5! = \dfrac{8!}{3!}$

Correct answer is (D): $\dfrac{8!}{3!}$

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Approach Solution -2

Given:
Word is VERTICAL, which has 8 letters.

Vowels in the word: E, I, A (3 vowels) 

Step 1: Choose positions for the 3 vowels out of 8 letters: $^8C_3$

Step 2: Arrange the remaining 5 consonants in those 5 positions: $5!$

Total number of ways: $^8C_3 \times 5! = \dfrac{8!}{3!}$

Correct option is (D): $\dfrac{8!}{3!}$

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Concepts Used:

Permutations

A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:

\(^nP_r = \frac{n!}{(n-r)!}\)

 nPr = permutation

 n = total number of objects

 r = number of objects selected

Types of Permutation

  • Permutation of n different things where repeating is not allowed
  • Permutation of n different things where repeating is allowed
  • Permutation of similar kinds or duplicate objects