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Each of the 6 distinct items can be placed in one of the 2 boxes, giving a total of \(2^6 = 64\) ways to distribute all items. However, this total includes the cases where one of the boxes is empty. We need to subtract these cases to ensure that both boxes contain at least one item. There are 2 scenarios where one box is empty: all items are in box 1 or all items are in box 2. Each scenario is counted once, so we subtract 2 from 64: \[ 64 - 2 = 62 \] Thus, there are 62 ways to distribute the 6 items into 2 boxes such that no box is empty.
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If \[ \int e^x (x^3 + x^2 - x + 4) \, dx = e^x f(x) + C, \] then \( f(1) \) is: