The number of \(\sigma\) bonds, \(\pi\)-bonds, and lone pairs of electrons present in the product Z in the given reaction sequence are respectively:
1. The given reaction starts with 1,2-dibromoethane, which undergoes zinc reduction to form ethene (C\(_2\)H\(_4\)).
2. In the presence of \( \text{H}^+ \)/H\(_2\)SO\(_4\), ethene undergoes rearrangement, leading to the formation of cyclopropane derivatives.
3. The final step involves heating with Cu at 573K, which facilitates further rearrangement leading to a conjugated system containing \( \sigma \) and \( \pi \) bonds, as well as lone pairs on heteroatoms.
Step 2: Counting the bonds and lone pairs.\( \sigma \) bonds: 9
\( \pi \) bonds: 1
Lone pairs: 2
Thus, the correct answer is (4) 9, 1, 2.
To solve the problem, we need to identify the number of sigma (σ) bonds, pi (π) bonds, and lone pairs of electrons present in the product \( Z \) formed in the given reaction sequence.
1. Analyzing the Reaction Sequence:
The reaction sequence involves the following steps:
The starting molecule contains a bromine atom attached to a benzene ring.
The first step involves the reaction with zinc (\( \text{Zn} \)) under heat, which eliminates the bromine atoms and forms a double bond, creating a cyclohexene intermediate.
The second step involves the reaction with sulfuric acid (\( \text{H}_2\text{SO}_4 \)), which leads to further rearrangement of the molecule.
The final step involves heating with copper (\( \text{Cu} \)) at 573K, which results in the final product \( Z \), which is a benzene ring with specific bonding and electron distribution.
2. Understanding the Product Z:
After analyzing the structure of the product \( Z \) (which is a benzene derivative), we can deduce:
There are 9 sigma (σ) bonds, including those in the aromatic ring and other single bonds in the molecule.
There is 1 pi (π) bond due to the double bonds in the aromatic ring.
There are 2 lone pairs of electrons on certain atoms (likely oxygen or nitrogen) in the product. Thus, the product \( Z \) has 9 sigma bonds, 1 pi bond, and 2 lone pairs of electrons.
3. Conclusion:
The correct answer is the number of sigma bonds = 9, pi bonds = 1, and lone pairs = 2.
Final Answer:
The correct option is (D): 9, 1, 2.
Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.