In the \(4 \times 4\) array shown below, each cell of the first three rows has either a cross (X) or a number.
\[
\begin{array}{|c|c|c|c|}
\hline
1 & X & 4 & 3
\hline
X & 5 & 5 & 4
\hline
3 & X & 6 & X
\hline
? & ? & ? & ?
\hline
\end{array}
\]
The number in a cell represents the count of the immediate neighboring cells (left, right, top, bottom, diagonals) NOT having a cross (X). Given that the last row has no crosses (X), the sum of the four numbers to be filled in the last row is: