Question

The number of ions present in tris(ethane-1,2-diamine)cobalt(III) sulphate is:

• A. 2
• B. 4
• C. 5
• D. 3

Hint:

Remember how to write the formulas for coordination compounds and how they dissociate into ions in solution.

Answer 1

The Correct Option is C

1. Write the chemical formula:

Tris(ethane-1,2-diamine)cobalt(III) sulphate is written as [Co(en)\(_3\)]\(_2\)(SO\(_4\))\(_3\), where 'en' represents ethane-1,2-diamine (NH\(_2\)CH\(_2\)CH\(_2\)NH\(_2\)).

2. Dissociation of the complex:

[Co(en)\(_3\)]\(_2\)(SO\(_4\))\(_3\) dissociates into ions as follows:

[Co(en)\(_3\)]\(_2\)(SO\(_4\))\(_3\) \( \rightarrow \) 2[Co(en)\(_3\)]\(^{3+}\) + 3SO\(_4^{2-}\)

3. Count the number of ions:

2 complex ions [Co(en)\(_3\)]\(^{3+}\)
3 sulphate ions SO\(_4^{2-}\)
Total ions = 2 + 3 = 5 ions

Therefore, the number of ions present in tris(ethane-1,2-diamine)cobalt(III) sulphate is 5.

Final Answer: 5.