We are given the following inequalities:
To understand when this inequality is true, we need to consider the cases where the absolute values change signs. Absolute value expressions change signs at the points where the values inside them are equal. So, we have:
So, for this inequality, the valid range of values for \( n \) is \( n < 80 \) and \( n > 60 \), which means \( n \) can be any integer between 61 and 79, inclusive. There are 19 integers in this range.
Similarly, we analyze the second inequality:
For this inequality, the valid range of values for \( n \) is \( n < 60 \) and \( n > 20 \), which means \( n \) can be any integer between 21 and 59, inclusive. There are 39 integers in this range.
Now, to find the integers that satisfy both inequalities, we need to find the intersection of the two ranges. The integers that satisfy both inequalities are those in the range \( [61, 59] \), which includes the integers from 61 to 59, inclusive.
The correct number of integers that satisfy the given inequalities is 19, as mentioned in your question.
So, the correct option is (D): \( \boxed{19} \).
We are given the inequality:
\[ 60 < |n - 100| < |n - 20| \]
The absolute value expressions represent the distance of \( n \) from the numbers 60, 100, and 20 on the number line. We need to analyze when the distance between \( n \) and 60 is less than the distance between \( n \) and 100, and when the distance between \( n \) and 100 is less than the distance between \( n \) and 20.
- For \( |n - 60| < |n - 100| \), we know that \( n \) must be closer to 60 than to 100. This means \( n \) must be greater than 40 and less than 60. Therefore, we get: \[ n > 40 \quad \text{and} \quad n < 60 \] - For \( |n - 100| < |n - 20| \), we know that \( n \) must be closer to 100 than to 20. This implies \( n \) must be greater than 60 and less than 80. Thus, we get: \[ n > 60 \quad \text{and} \quad n < 80 \]
The two inequalities combine to give the valid range of values for \( n \). The intersection of \( 40 < n < 60 \) and \( 60 < n < 80 \) is: \[ 61 \leq n \leq 79 \] Thus, the integers in this range are \( 61, 62, 63, \dots, 79 \). The total number of integers is 19.
The correct option is \( \boxed{19} \).
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is:
| LIST I | LIST II | ||
| A. | The solution set of the inequality \(-5x > 3, x\in R\), is | I. | \([\frac{20}{7},∞)\) |
| B. | The solution set of the inequality is, \(\frac{-7x}{4} ≤ -5, x\in R\) is, | II. | \([\frac{4}{7},∞)\) |
| C. | The solution set of the inequality \(7x-4≥0, x\in R\) is, | III. | \((-∞,\frac{7}{5})\) |
| D. | The solution set of the inequality \(9x-4 < 4x+3, x\in R\) is, | IV. | \((-∞,-\frac{3}{5})\) |
At InnovateX, six employees, Asha, Bunty, Chintu, Dolly, Eklavya, and Falguni, were split into two groups of three each: Elite led by Manager Kuku, and Novice led by Manager Lalu. At the end of each quarter, Kuku and Lalu handed out ratings to all members in their respective groups. In each group, each employee received a distinct integer rating from 1 to 3. & nbsp;
The score for an employee at the end of a quarter is defined as their cumulative rating from the beginning of the year. At the end of each quarter the employee in Novice with the highest score was promoted to Elite, and the employee in Elite with the minimum score was demoted to Novice. If there was a tie in scores, the employee with a higher rating in the latest quarter was ranked higher.
1. Asha, Bunty, and Chintu were in Elite at the beginning of Quarter 1. All of them were in Novice at the beginning of Quarter 4.
2. Dolly and Falguni were the only employees who got the same rating across all the quarters.
3. The following is known about ratings given by Lalu (Novice manager):
– Bunty received a rating of 1 in Quarter 2. & nbsp;
– Asha and Dolly received ratings of 1 and 2, respectively, in Quarter 3.
Five countries engage in trade with each other. Each country levies import tariffs on the other countries. The import tariff levied by Country X on Country Y is calculated by multiplying the corresponding tariff percentage with the total imports of Country X from Country Y. The radar chart below depicts different import tariff percentages charged by each of the five countries on the others. For example, US (the blue line in the chart) charges 20%, 40%, 30%, and 30% import tariff percentages on imports from France, India, Japan, and UK, respectively. The bar chart depicts the import tariffs levied by each county on other countries. For example, US charged import tariff of 3 billion USD on UK.
Assume that imports from one country to an other equals the exports from the latter to the former. The trade surplus of Country X with Country Y is defined as follows. Trade surplus = Exports from Country X to Country Y Imports to Country X from Country Y. A negative trade surplus is called trade deficit.
A train travels from Station A to Station E, passing through stations B, C, and D, in that order. The train has a seating capacity of 200. A ticket may be booked from any station to any other station ahead on the route, but not to any earlier station. A ticket from one station to another reserves one seat on every intermediate segment of the route. For example, a ticket from B to E reserves a seat in the intermediate segments B– C, C– D, and D–E. The occupancy factor for a segment is the total number of seats reserved in the segment as a percentage of the seating capacity. The total number of seats reserved for any segment cannot exceed 200. The following information is known. 1. Segment C– D had an occupancy factor of 952. Exactly 40 tickets were booked from B to C and 30 tickets were booked from B to E. 3. Among the seats reserved on segment D– E, exactly four-sevenths were from stations before C. 4. The number of tickets booked from A to C was equal to that booked from A to E, and it was higher than that from B to E. 5. No tickets were booked from A to B, from B to D and from D to E. 6. The number of tickets booked for any segment was a multiple of 10.