Question:

The number of d-electrons in \( \text{Cr}^{3+} \) ion (\( Z = 24 \)) is

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For transition metal ions, electrons are first removed from the 4s orbital and then from the 3d orbitals.
Updated On: May 15, 2025
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The Correct Option is C

Solution and Explanation

To find the number of d-electrons in \( \text{Cr}^{3+} \), we need to first determine the electron configuration of the neutral chromium atom (\( Z = 24 \)). Chromium has an atomic number of 24, so its electron configuration in the ground state is: \[ \text{Cr}: [Ar] \, 3d^5 \, 4s^1 \] When chromium loses 3 electrons to form the \( \text{Cr}^{3+} \) ion, the electrons are removed first from the 4s orbital and then from the 3d orbital. Thus, the electron configuration of \( \text{Cr}^{3+} \) is: \[ \text{Cr}^{3+}: [Ar] \, 3d^3 \] Therefore, the number of d-electrons in \( \text{Cr}^{3+} \) is 3. Thus, the correct answer is \( \boxed{3} \).
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