Explanation:
Given:Organometallic compound : \(Co_2(CO)_8\) We have to find the number of bridging \(CO\) ligands and \(Co-Co\) bond.
The structure of \(Co_2(CO)_8\) is:
The there are two \(CO\) bridging ligands and one \(Co-Co\) bond.
\(\text{Hence, the correct option is (D):}\) \(2 \;and \;1\)
Ans: \(Co_2(CO)_8\) is a cobalt carbonyl complex, in this there are two bridging \(CO\) ligands and one \(Co-Co\) bond. In the compound there are four \(CO\) ligands, of these two of them are the bridging ligands. They are called bridging ligands because they bridge between the two cobalt atoms.
On the other hand, there is only one \(Co-Co\) bond in the complex. The two cobalt atoms present are connected by a single covalent bond.
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]