In a unit cell, the number of atoms can be determined based on the arrangement of atoms in the lattice.
1. Body-Centered Cubic (BCC): - In a body-centered cubic unit cell, there is 1 atom at each corner of the cube (8 corners in total) and 1 atom at the center of the cube.
- The atoms at the corners are shared among 8 unit cells, so each corner atom contributes 1/8 of an atom to the unit cell.
- Therefore, the total number of atoms in a body-centered cubic unit cell is:
(8 × 1/8) + 1 = 2 atoms.
2. Face-Centered Cubic (FCC): - In a face-centered cubic unit cell, there is 1 atom at each corner of the cube (8 corners) and 1 atom at the center of each face (6 faces in total).
- The atoms at the corners are shared among 8 unit cells, so each corner atom contributes 1/8 of an atom.
- The atoms at the faces are shared between 2 unit cells, so each face-centered atom contributes 1/2 of an atom.
- Therefore, the total number of atoms in a face-centered cubic unit cell is:
(8 × 1/8) + (6 × 1/2) = 1 + 3 = 4 atoms.
Answer: 2 and 4
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of: