We are given the function:
\[
f(x) = e^{-x} - x
\]
and the initial guess for the root is $x_0 = 0$. The Newton-Raphson method is given by the formula:
\[
x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}
\]
First, we need to compute the derivative of the function:
\[
f'(x) = \frac{d}{dx}(e^{-x} - x) = -e^{-x} - 1
\]
Now, we use the Newton-Raphson formula for the first iteration with $x_0 = 0$:
\[
x_1 = x_0 - \frac{f(x_0)}{f'(x_0)}
\]
Substitute the values into the formula:
\[
f(0) = e^{-0} - 0 = 1 \text{and} f'(0) = -e^{0} - 1 = -1 - 1 = -2
\]
Now, calculate $x_1$:
\[
x_1 = 0 - \frac{1}{-2} = 0 + 0.5 = 0.50
\]
Therefore, the estimate of the root after the first iteration is $0.50$.