The negation of \( \sim S \vee ( \sim R \wedge S) \) \(\text{ is equivalent to}\)
Step 1: The given expression is \( \sim S \vee ( \sim R \wedge S) \).
Step 2: To find the negation, apply De Morgan's law. The negation of a disjunction (\( \vee \)) becomes a conjunction (\( \wedge \)) of the negations of each term. So we need to negate each term separately:
\[ \sim (\sim S \vee (\sim R \wedge S)) = \sim \sim S \wedge \sim (\sim R \wedge S) \]
Step 3: Simplify \( \sim \sim S \) to \( S \). Now apply De Morgan's law to \( \sim (\sim R \wedge S) \), which becomes \( \sim \sim R \vee \sim S \), i.e., \( R \vee \sim S \). Therefore, the expression becomes:
\[ S \wedge (R \vee \sim S) \]
Step 4: However, the original expression has \( \sim S \) outside the parentheses, so this simplifies to:
\[ S \wedge R \] Thus, the negation is \( S \wedge R \), which is option (c).
"In order to be a teacher, one must graduate from college. All poets are poor. Some Mathematicians are poets. No college graduate is poor."
Which of the following is true?