Step 1: Understanding the conditions.
For \( p \land q = \text{F} \) and \( p \rightarrow q = \text{F} \), we know the following: - \( p \land q = \text{F} \) implies that at least one of \( p \) or \( q \) must be false. - \( p \rightarrow q = \text{F} \) implies that \( p \) is true and \( q \) is false.
Step 2: Conclusion.
Thus, the only possible combination is \( p = \text{F} \) and \( q = \text{T} \).
Therefore, the correct answer is (C).
The negation of \( \sim S \vee ( \sim R \wedge S) \) \(\text{ is equivalent to}\)