To determine the bond order in [NO]−, we need to use molecular orbital theory. The electronic configuration of NO− is the same as the molecular orbital configuration of NO, but with one additional electron due to the negative charge. In the case of NO, the molecular orbital diagram suggests a bond order of 2.
The addition of one electron to NO, forming [NO]−, increases the number of electrons in the bonding molecular orbitals, but does not change the bond order significantly because the additional electron does not affect the bond order calculated by the molecular orbital theory.
Thus, the bond order of N–O in [NO]− remains 2, which is similar to that of NO.
What is the empirical formula of a compound containing 40% sulfur and 60% oxygen by mass?
Match the LIST-I with LIST-II.
Choose the correct answer from the options given below :
Which of the following molecules(s) show/s paramagnetic behavior?
$\mathrm{O}_{2}$
$\mathrm{N}_{2}$
$\mathrm{F}_{2}$
$\mathrm{S}_{2}$
Given below are two statements:
Statement I : The N-N single bond is weaker and longer than that of P-P single bond
Statement II : Compounds of group 15 elements in +3 oxidation states readily undergo disproportionation reactions.
In the light of above statements, choose the correct answer from the options given below
One mole of a monoatomic ideal gas starting from state A, goes through B and C to state D, as shown in the figure. Total change in entropy (in J K\(^{-1}\)) during this process is ............... 
The number of chiral carbon centers in the following molecule is ............... 
A tube fitted with a semipermeable membrane is dipped into 0.001 M NaCl solution at 300 K as shown in the figure. Assume density of the solvent and solution are the same. At equilibrium, the height of the liquid column \( h \) (in cm) is ......... 
An electron at rest is accelerated through 10 kV potential. The de Broglie wavelength (in A) of the electron is .............