To determine the bond order in [NO]−, we need to use molecular orbital theory. The electronic configuration of NO− is the same as the molecular orbital configuration of NO, but with one additional electron due to the negative charge. In the case of NO, the molecular orbital diagram suggests a bond order of 2.
The addition of one electron to NO, forming [NO]−, increases the number of electrons in the bonding molecular orbitals, but does not change the bond order significantly because the additional electron does not affect the bond order calculated by the molecular orbital theory.
Thus, the bond order of N–O in [NO]− remains 2, which is similar to that of NO.
One mole of a monoatomic ideal gas starting from state A, goes through B and C to state D, as shown in the figure. Total change in entropy (in J K\(^{-1}\)) during this process is ...............
The number of chiral carbon centers in the following molecule is ...............
A tube fitted with a semipermeable membrane is dipped into 0.001 M NaCl solution at 300 K as shown in the figure. Assume density of the solvent and solution are the same. At equilibrium, the height of the liquid column \( h \) (in cm) is .........
An electron at rest is accelerated through 10 kV potential. The de Broglie wavelength (in A) of the electron is .............