Question:

The motor of an engine is rotating about its axis with an angular velocity of 100 rev/m. If conies to rest in 15s, after being switched off. Assuming constant angular deceleration. What are the numbers of revolutions made by it before coming to rest?

Updated On: Aug 15, 2022
  • 12.5
  • 40
  • 32.6
  • 15.6
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The Correct Option is A

Solution and Explanation

$ 0={{\omega }_{0}}-\alpha t $ $ \alpha =\frac{{{\omega }_{0}}}{t}=\frac{(100\times 2\pi )/60}{15} $ $ =0.7\,\text{rad/s} $ Now, angle rotated before coming to rest $ \theta =\frac{\omega _{0}^{2}}{2\alpha } $ $ \theta =\frac{{{\left( \frac{100\times 2\pi }{60} \right)}^{2}}}{2\times 0.7} $ $ =78.33\,\text{rad} $ Numbers of rotations $ \eta =\frac{\theta }{2\pi }=12.5 $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration