Question:

An elliptically shaped ring of dimensions shown in figure just touches, the horizontal surface of a liquid of surface tension S. The force required to pull the ring away from the liquid surface is

Updated On: Jun 23, 2023
  • $ 2\pi (\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S $
  • $ \pi ({{a}_{1}}+{{b}_{1}}+{{a}_{2}}+{{b}_{2}})S $
  • $ \pi \left( \frac{{{a}_{1}}+{{a}_{2}}}{2}+\frac{{{b}_{1}}+{{b}_{2}}}{2} \right)S $
  • $ \sqrt{2\pi }(\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S $
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The Correct Option is A

Solution and Explanation

Internal mean radius $ {{r}_{1}}\sqrt{{{a}_{1}}{{b}_{1}}} $ Internal circumference of the ring $ =2\pi {{r}_{1}}=2\pi \sqrt{{{a}_{1}}{{b}_{1}}} $ External mean radius $ {{r}_{2}}=\sqrt{{{a}_{2}}{{b}_{2}}} $ External circumference of the ring $ =2\pi {{r}_{2}}=2\pi \sqrt{{{a}_{2}}{{b}_{2}}} $ Thus, force required $ F=2\pi \sqrt{{{a}_{1}}{{b}_{1}}S}+2\pi \sqrt{{{a}_{2}}{{b}_{2}}}\,S $ $ =2\pi (\sqrt{{{a}_{1}}{{b}_{1}}}+\sqrt{{{a}_{2}}{{b}_{2}}})S $
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Concepts Used:

Surface Tension

The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.

Surface tension is defined as,

The ratio of the surface force F to the length L along which the force acts.

Mathematically, the surface tension formula can be expressed as follows:

T=F/L

Where,

  • F is the force per unit length
  • L is the length in which force act
  • T is the surface tension of the liquid

Read More: Detergents and Surface Tension

Factors affecting surface tension:

  • Impurities: The surface tension decreases with the addition of impurities.
  • Surfactants: Adding surfactants in liquids lowers the tension of water making it interrupt aside or get susceptible.
  • Temperature: The surface tension of a liquid reduces as the temperature rises.

The Unit of Surface Tension:

The SI unit of Surface Tension is Newton per Meter or N/m.