The correct answer is (A): Ce(At. No. 58)
Explanation:
Ce → [Xe]4f1 5d1 6s2
Ce+4 → [xe] 4f° 5d° 6s°
Cerium in +4 oxidation state acquires inert gas configuration.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)