Question:
The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?
The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?
Updated On: Feb 4, 2026
- Ce(At. No. 58)
- La (At. No. 57)
- Lu (At. No. 71)
- Gd(At. No. 64)
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The Correct Option is A
Solution and Explanation
The correct answer is (A): Ce(At. No. 58)
Explanation:
Ce → [Xe]4f1 5d1 6s2
Ce+4 → [xe] 4f° 5d° 6s°
Cerium in +4 oxidation state acquires inert gas configuration.
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