Question:

The molecular electronic configuration of $Be_2$ is:

Updated On: Jan 30, 2025
  • $ \sigma 1 s^2 \sigma^* 1s^2 \sigma2s^2 \sigma^* 2p^2$
  • $KK \sigma2s^2$
  • $ \sigma1s^2 \sigma^* 1s^2 \sigma 2s^2 \sigma^* 2s^2$
  • none of the above
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The Correct Option is C

Solution and Explanation

Total no. of electrons in $Be _{2}=8$.
Electronic configuration according to molecular orbital theory:
$\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}=\sigma^{*} 2 s^{2}$
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Concepts Used:

Group 2 Elements

The group two or alkaline earth metals are s-block elements with two electrons in their s-orbital. They are alkaline earth metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkaline earth metals are characterized by two s-electrons. This group of elements includes:

  • Beryllium (Be)
  • Magnesium (Mg)
  • Calcium (Ca)
  • Strontium (Sr)
  • Barium (Ba)
  • Radium (Ra)

Elements whose atoms have their s-subshell filled with their two valence electrons are called alkaline earth metals. Their general electronic configuration is [Noble gas] ns2. They occupy the second column of the periodic table and so-called as group two metals also.