Step 1: The binomial expansion of \( (10x + x^{10})^{10} \) is given by:
\[
(10x + x^{10})^{10} = \sum_{r=0}^{10} \binom{10}{r} (10x)^{10-r} (x^{10})^r.
\]
Step 2: The general term is:
\[
\binom{10}{r} (10x)^{10-r} (x^{10})^r = \binom{10}{r} 10^{10-r} x^{10-r + 10r}.
\]
This simplifies to:
\[
\binom{10}{r} 10^{10-r} x^{10 + 9r}.
\]
Step 3: The middle term corresponds to \( r = 5 \), as the series has 11 terms. Thus, the middle term is:
\[
\binom{10}{5} 10^5 x^{10 + 9(5)} = \binom{10}{5} 10^5 x^{55}.
\]
Step 4: Hence, the middle term is \( 10C5 \).