To determine which metal produces hydrogen gas (H\(_2\)) with both dil. HCl and NaOH(aq), let's analyze the reactivity of different metals with these reagents.
1. With dilute HCl: The metal must react with hydrochloric acid (HCl) to produce hydrogen gas. For example: \[ \text{Zn} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2(g) \] Zinc (Zn) reacts with dilute hydrochloric acid to produce hydrogen gas.
2. With NaOH(aq): The metal must also react with aqueous sodium hydroxide (NaOH) to produce hydrogen gas. This occurs with metals like zinc: \[ \text{Zn} + 2\text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 + \text{H}_2(g) \] Zinc reacts with sodium hydroxide to form hydrogen gas. Thus, zinc (Zn) is the only metal that reacts with both dilute HCl and NaOH(aq) to produce hydrogen gas. Thus, the correct answer is \(Zn\).
The correct option is(B): \(Zn\)
When metals react with dilute acids like hydrochloric acid (HCl), they produce hydrogen gas (\( H_2 \)) through a displacement reaction. Similarly, some metals also react with bases like sodium hydroxide (NaOH) to release hydrogen gas. Among the metals:
Thus, the correct answer is \({(B)} \), as zinc is the metal that reacts with both dilute hydrochloric acid and sodium hydroxide to release hydrogen gas.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).