The median class of the following table will be:
The median class of the following table will be:
Show Hint
- 10–20
- 20–30
- 30–40
- 40–50
The Correct Option is C
Solution and Explanation
Step 1: Find cumulative frequencies. 
Step 2: Determine $N/2$.
\[ N = 49 \Rightarrow N/2 = 24.5 \] Step 3: Identify the median class.
The class in which the cumulative frequency first exceeds 24.5 is 30–40.
Step 4: Conclusion.
Hence, the median class is 30–40.
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