Question

The median class of the following frequency table will be 

• A. 0–5
• B. 5–10
• C. 10–15
• D. 15–20

Hint:

To find the median class, calculate cumulative frequencies and find the class where \(\frac{N}{2}\) lies.

Answer 1

The Correct Option is D

Step 1: Find the total frequency.
\[ N = 4 + 6 + 5 + 8 + 2 = 25 \]
Step 2: Compute \(\frac{N}{2}\).
\[ \frac{N}{2} = \frac{25}{2} = 12.5 \]
Step 3: Identify the median class.
The median class is the class whose cumulative frequency just exceeds 12.5.
Cumulative frequencies: \[ 0–5: 4, \quad 5–10: 10, \quad 10–15: 15, \quad 15–20: 23, \quad 20–25: 25 \] The cumulative frequency just greater than 12.5 is 15, corresponding to the class 10–15.
Step 4: Recheck based on median formula.
However, as per the standard definition, the class interval containing \(\frac{N}{2}\) = 12.5 is 10–15.
Step 5: Conclusion.
Hence, the median class is 10–15.