Question:

The mean of the first n terms of the A.P. (a + d) + (a + 3d) + (a + 5d) + .... is

Updated On: Jun 23, 2023
  • $a + \frac{n}{2} d $
  • $a + nd$
  • $a + n^2 d$
  • none of these
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The Correct Option is B

Solution and Explanation

Required A.M. $ = \frac{1}{n} \left[\left(a+ d\right) +\left(a+ 3d\right) +\left(a+ 5d\right) +..\text{upto}\, n\, \text{terms}\right]$ $ = \frac{1}{n} \times\frac{n}{2}\left\{2\left(a+d\right) + \left(n-1\right)\left(2d\right)\right\} $ $= \frac{1}{2}\left\{2a+2d+2nd -2d\right\} = a+nd.$
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Concepts Used:

Mean Deviation

A statistical measure that is used to calculate the average deviation from the mean value of the given data set is called the mean deviation.

The Formula for Mean Deviation:

The mean deviation for the given data set is calculated as:

Mean Deviation = [Σ |X – µ|]/N

Where, 

  • Σ represents the addition of values
  • X represents each value in the data set
  • µ represents the mean of the data set
  • N represents the number of data values

Grouping of data is very much possible in two ways:

  1. Discrete Frequency Distribution
  2. Continuous Frequency Distribution