Question:
The maximum power efficiency of an AM modulator is _______.
The maximum power efficiency of an AM modulator is _______.
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AM efficiency is capped at 50% due to constant power in carrier which doesn't carry information.
Updated On: Jun 23, 2025
- 25%
- 50%
- 75%
- 100%
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The Correct Option is B
Solution and Explanation
In AM, the total power consists of:
\[
P_{total} = P_c + P_{USB} + P_{LSB}
\]
Carrier consumes most power, sidebands carry information.
Maximum efficiency occurs at 100% modulation: \[ \eta = \frac{P_{USB} + P_{LSB}}{P_{total}} = \frac{2P_m}{P_c + 2P_m} \] At $m = 1$, $\eta = 50%$ Hence, AM cannot be more than 50% efficient in ideal conditions.
Maximum efficiency occurs at 100% modulation: \[ \eta = \frac{P_{USB} + P_{LSB}}{P_{total}} = \frac{2P_m}{P_c + 2P_m} \] At $m = 1$, $\eta = 50%$ Hence, AM cannot be more than 50% efficient in ideal conditions.
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