The equation for the equivalent of Ag is:
$$\text{Eq. of Ag} = \text{Eq. of } O_2$$
Let x grams of silver be displaced.
$$\frac{x}{108} = \frac{5.6}{22.7} \times 4$$
Using the molar volume of gas at STP (22.7 L), we get:
$$x = 106.57 \, \text{g}$$
Thus, the answer is approximately 107 g.
Alternatively, using 22.4 L as the molar volume at STP:
$$\frac{x}{108} = \frac{5.6}{22.4} \times 4$$
which gives $$x = 108 \, \text{g}$$.