The major products formed when one mole of \( \text{CH}_3\text{CH}_2\text{CH}(\text{CH}_3)\text{CH}_2\text{OCH}_2\text{CH}_3 \) is treated with one mole of HI are:
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- 2-methylbutan-1-ol and iodoethane
- ethanol and 2-methylidobutane
- 2-methylbutan-2-ol and iodomethane
- 2-methylbutan-1-ol and iodomethane
- 2-methylbutan-1-ol and ethene
The Correct Option is A
Solution and Explanation
The reaction of HI with ethers follows acidic cleavage, where the more hindered alkyl group retains the OH, while the less hindered group forms an iodoalkane.
- The larger group (2-methylbutyl) forms 2-methylbutan-1-ol.
- The smaller group (ethyl) forms iodoethane.
Thus, the major products are 2-methylbutan-1-ol and iodoethane.
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