The reaction proceeds as follows: 1. The anisole (methoxybenzene) undergoes nitration with \( \text{HNO}_3/\text{H}_2\text{SO}_4 \) to form the product (A), which is 4-nitroanisole. 2. Subsequently, bromination with \( \text{Br}_2 \) (in the presence of excess iron) results in the brominated product (B), 4-bromo-2-nitroanisole.
Thus, the major products are (A) and (B) as represented in option (2).