Question:

The major product of the reaction between CH$_3$CH$_2$ONa and (CH$_3$)$_3$CCl in ethanol is:

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Tertiary alkyl halides preferentially undergo elimination (E2) instead of substitution due to steric hindrance.
Updated On: Feb 3, 2025
  • CH$_3$CH$_2$OC(CH$_3$)$_3$
  • CH$_2$ = C(CH$_3$)$_2$
  • CH$_3$CH$_2$C(CH$_3$)$_3$
  • CH$_3$CH = CHCH$_3$
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Reaction Mechanism 
The given reaction involves sodium ethoxide (CH$_3$CH$_2$ONa) and tert-butyl chloride [(CH$_3$)$_3$CCl] in ethanol. Tertiary alkyl halides undergo elimination (E2) rather than substitution due to steric hindrance. 
Step 2: Identifying the Major Product 
Since sodium ethoxide is a strong base, elimination occurs via the E2 mechanism, leading to the formation of an alkene. The product formed is isobutene (\( CH_2 = C(CH_3)_2 \)). Thus, the correct answer is (B).

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