The major product of the following reaction is:
The major product of the following reaction is:
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- 2-Phenylhepta-2,4-diene
- 6-Phenylhepta-3,5-diene
- 6-Phenylhepta-2,4-diene
- 2-Phenylhepta-2,5-diene
The Correct Option is C
Solution and Explanation
The given reaction involves a dehydrohalogenation process, where a halogen (Br) is eliminated in the presence of an excess base, KOH in ethanol. This reaction typically leads to the formation of alkenes by the elimination of H and Br atoms.
Since the reagent is in excess, it leads to a conjugated diene product.
The elimination occurs in such a way that the resulting product has two double bonds conjugated with the phenyl group.
The correct product formed in this reaction is 6-Phenylhepta-2,4-diene, as it has the conjugation in positions 2 and 4.
Top Questions on Amines
- Give the structures of A, B, and C in the following reaction sequences: (i)\; \(\mathrm{CH_3CH_2I} \xrightarrow[\ ]{\mathrm{NaCN}} A \xrightarrow[\ ]{\;\;HO^-\;/\;H_2O\;\;} B \xrightarrow[\;Br_2/NaOH\;]{} C\)
(ii)\; \(\mathrm{C_6H_5N_2^+Cl^-} \xrightarrow[\ ]{\mathrm{CuCN}} A \xrightarrow[\ ]{\;H_3O^+\;} B \xrightarrow[\ \Delta\ ]{\;NH_3\;} C\)
(iii)\; \(\mathrm{CH_3CH_2Br} \xrightarrow[\ ]{\mathrm{KCN}} A \xrightarrow[\ ]{\mathrm{LiAlH_4}} B \xrightarrow[\;273\,K\;]{\;HNO_2\;} C\) - How can you obtain the following?
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(i) Ethanoic acid to methanamineWhich of the following amine(s) show(s) positive carbamylamine test?
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